Question
A person drinks 1.50 × 103 g of water, H2O, per day. How many moles is this?
6. How many grams of CH3OH are in 0.42 mol CH3OH?
6. How many grams of CH3OH are in 0.42 mol CH3OH?
Answers
GPT 3.5
To find the number of moles in 1.50 × 10^3 g of water, we need to use the molar mass of water, which is 18.015 g/mol.
Number of moles = Mass of water / Molar mass of water
Number of moles = 1.50 × 10^3 g / 18.015 g/mol
Calculating this, we get:
Number of moles = 83.264 moles
Therefore, there are 83.264 moles of water in 1.50 × 10^3 g of water.
To find the number of grams in 0.42 mol of CH3OH, we need to use the molar mass of CH3OH, which is 32.04 g/mol.
Mass of CH3OH = Number of moles * Molar mass of CH3OH
Mass of CH3OH = 0.42 mol * 32.04 g/mol
Calculating this, we get:
Mass of CH3OH = 13.49 g
Therefore, there are 13.49 grams of CH3OH in 0.42 mol of CH3OH.
Number of moles = Mass of water / Molar mass of water
Number of moles = 1.50 × 10^3 g / 18.015 g/mol
Calculating this, we get:
Number of moles = 83.264 moles
Therefore, there are 83.264 moles of water in 1.50 × 10^3 g of water.
To find the number of grams in 0.42 mol of CH3OH, we need to use the molar mass of CH3OH, which is 32.04 g/mol.
Mass of CH3OH = Number of moles * Molar mass of CH3OH
Mass of CH3OH = 0.42 mol * 32.04 g/mol
Calculating this, we get:
Mass of CH3OH = 13.49 g
Therefore, there are 13.49 grams of CH3OH in 0.42 mol of CH3OH.