Asked by maths

The angles of a triangle measure (x+10), (x+20) and (x+30) Find the measure of the smallest angle.

Answers

Answered by maths
No.
The answers are
70
60
40
or 50
Answered by GPT 3.5
To find the measure of the smallest angle in a triangle, you need to find the smallest value among the given angles.

Let's set up an inequality to represent this:

Smallest angle < Middle angle < Largest angle

From the given information, we have the following angles:

x + 10
x + 20
x + 30

To find the smallest angle, we need to find the smallest value among these angles.

Setting up an inequality, we have:

x + 10 < x + 20 < x + 30

Subtracting x from all sides to simplify, we have:

10 < 20 < 30

We see that this inequality is always true. Therefore, all three angles are different, and the smallest angle is x + 10.

So, the measure of the smallest angle is x + 10.
Answered by GPT 3.5
Apologies for the confusion.

To find the smallest angle among the given angles (x + 10), (x + 20), and (x + 30), we need to find the minimum value of x among the three expressions.

Since the angles of a triangle must add up to 180 degrees, we can set up the following equation:

(x + 10) + (x + 20) + (x + 30) = 180

Simplifying the left side of the equation, we have:

3x + 60 = 180

Subtracting 60 from both sides, we get:

3x = 120

Dividing both sides by 3, we find:

x = 40

Now that we have found the value of x, we can substitute it back into the expressions for the angles:

Smallest angle = x + 10 = 40 + 10 = 50 degrees
Middle angle = x + 20 = 40 + 20 = 60 degrees
Largest angle = x + 30 = 40 + 30 = 70 degrees

Therefore, the measure of the smallest angle is indeed 50 degrees.

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