Asked by Salman
Find the derivative of the inverse of the function
f(x)=6x+(9x^21) when x=-15
f(x)=6x+(9x^21) when x=-15
Answers
Answered by
Reiny
I think you might have a typo
the power x^21 looks totally "out of character".
Anyway, I would write the function as
y = 6x + 9x^21
then its inverse is
x = 6y + 9y^21
differentiate implicitly with respect to x
1 = 6dy/dx + (189y^20)dy/dx
factoring and simplifying we get
dy/dx = 1/(6 + 189y^20)
so when x=-15 , in the inverse we get
-15 = 9y^21 + 6y
9y^21 + 6y + 15 = 0
I just noticed that y = -1 is a solution
so dy/dx = 1/(6 + (-1)^20)
= 1/(6+1) = 1/7
the power x^21 looks totally "out of character".
Anyway, I would write the function as
y = 6x + 9x^21
then its inverse is
x = 6y + 9y^21
differentiate implicitly with respect to x
1 = 6dy/dx + (189y^20)dy/dx
factoring and simplifying we get
dy/dx = 1/(6 + 189y^20)
so when x=-15 , in the inverse we get
-15 = 9y^21 + 6y
9y^21 + 6y + 15 = 0
I just noticed that y = -1 is a solution
so dy/dx = 1/(6 + (-1)^20)
= 1/(6+1) = 1/7
Answered by
Salman
thnx, that helped alot!
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