What is the probability of drawing an ace and a 10, Jack, Queen, or King from a deck of cards?
5 answers
16 out of 52 or 4 out of 13
I don't understand how you did that.
(You're supposed to draw 2 cards - an ace and a 10, an ace and a Jack, an ace and a Queen, or an ace and a King).
(You're supposed to draw 2 cards - an ace and a 10, an ace and a Jack, an ace and a Queen, or an ace and a King).
prob = 2(4/52)(16/51) = 32/663 or 0.02413
or using the "choose" notation,
C(4,1)C(16,1)/(52,2) = 64/1326 = 32/663
or using the "choose" notation,
C(4,1)C(16,1)/(52,2) = 64/1326 = 32/663
10
Apologies for the confusion. The probability of drawing an ace and either a 10, Jack, Queen, or King from a deck of cards can be calculated as follows:
First, we determine the probability of drawing an Ace from the deck. There are 4 Aces in a deck of 52 cards, so the probability of drawing an Ace is 4/52.
Next, we determine the probability of drawing a 10, Jack, Queen, or King from the remaining cards after drawing an Ace. Since there are 16 of these cards (4 each), the probability of drawing one of them is 16/51.
To find the probability of both events happening, we multiply the two probabilities:
P(Ace and 10, J, Q, or K) = (4/52) * (16/51)
= 64/2652
= 8/327.
So, the probability of drawing an Ace and either a 10, Jack, Queen, or King from a deck of cards is 8/327.
First, we determine the probability of drawing an Ace from the deck. There are 4 Aces in a deck of 52 cards, so the probability of drawing an Ace is 4/52.
Next, we determine the probability of drawing a 10, Jack, Queen, or King from the remaining cards after drawing an Ace. Since there are 16 of these cards (4 each), the probability of drawing one of them is 16/51.
To find the probability of both events happening, we multiply the two probabilities:
P(Ace and 10, J, Q, or K) = (4/52) * (16/51)
= 64/2652
= 8/327.
So, the probability of drawing an Ace and either a 10, Jack, Queen, or King from a deck of cards is 8/327.