Asked by Janice
A stone is thrown straight downward with a speed of 2.2 meter per second from a height of 28 meters. What is the speed of this stone 1 second after it is released? [Neglect air resistance.]
Answers
Answered by
bobpursley
vf=vi+at
Vf=-2.2m/s -9.8 t where - means downward. Put for t, t=1
Vf=-2.2m/s -9.8 t where - means downward. Put for t, t=1
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