Asked by Lauren
A rock is dropped from a height of 100m.
a) how long does it take to fall the first 50m?
b)How long does it take to fall the last 50m?
Which equation would I use to solve this problems with?
For a) use s=(1/)g*t^2 where s=50m and g=9.8m/s^2 and solve for t.
For b)use s=(1/)g*t^2 where s=1000m and g=9.8m/s^2, solve for t and subtract the result of part a).
You use the same formula, but you look at the total time minus some partial time. Does that make sense?
a) how long does it take to fall the first 50m?
b)How long does it take to fall the last 50m?
Which equation would I use to solve this problems with?
For a) use s=(1/)g*t^2 where s=50m and g=9.8m/s^2 and solve for t.
For b)use s=(1/)g*t^2 where s=1000m and g=9.8m/s^2, solve for t and subtract the result of part a).
You use the same formula, but you look at the total time minus some partial time. Does that make sense?
Answers
Answered by
Yusuf
A stone propelled from a catapult with a speed of 50m-s attains a height of 100m calcutate
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