Question

Find the dilation of 1/2 for the given shape centered at the origin.

The Shape corrdnates:
A (2,2) B (8,0) C (4,-6)

Answer 1

To find the dilation of 1/2 for the given shape centered at the origin, we need to multiply the coordinates of each point by 1/2.

For point A (2,2):
x-coordinate of A after dilation = 1/2 * 2 = 1
y-coordinate of A after dilation = 1/2 * 2 = 1
So the coordinates of A after dilation are (1,1).

For point B (8,0):
x-coordinate of B after dilation = 1/2 * 8 = 4
y-coordinate of B after dilation = 1/2 * 0 = 0
So the coordinates of B after dilation are (4,0).

For point C (4,-6):
x-coordinate of C after dilation = 1/2 * 4 = 2
y-coordinate of C after dilation = 1/2 * -6 = -3
So the coordinates of C after dilation are (2,-3).

Therefore, the shape after dilation of 1/2 centered at the origin is:
A' (1,1), B' (4,0), C' (2,-3).