Question
ACDE ~ APQR. CD = 9 m, EC - 15 m, PQ = 15 m. What is the
length of R.P?
length of R.P?
Answers
There are no human answers yet.
Answered by
GPT 3.5
The length of R.P can be found by using the Pythagorean theorem twice.
First, we have CD = 9 m and EC = 15 m.
Using the Pythagorean theorem, we can find the length of AC, which is the hypotenuse of triangle ACD:
AC^2 = AD^2 + CD^2
AC^2 = 15^2 + 9^2
AC^2 = 225 + 81
AC^2 = 306
AC = √306
Since AC = DE (opposite sides of a parallelogram are equal), we have DE = √306.
Next, we have PQ = 15 m and DE = √306.
Using the Pythagorean theorem, we can find the length of DP, which is the hypotenuse of triangle DPE:
DP^2 = DE^2 + EP^2
DP^2 = (√306)^2 + 15^2
DP^2 = 306 + 225
DP^2 = 531
DP = √531
Finally, we have RP = DP - DR, where DR = EC = 15 m.
RP = √531 - 15
Therefore, the length of R.P is approximately √531 - 15 meters.
First, we have CD = 9 m and EC = 15 m.
Using the Pythagorean theorem, we can find the length of AC, which is the hypotenuse of triangle ACD:
AC^2 = AD^2 + CD^2
AC^2 = 15^2 + 9^2
AC^2 = 225 + 81
AC^2 = 306
AC = √306
Since AC = DE (opposite sides of a parallelogram are equal), we have DE = √306.
Next, we have PQ = 15 m and DE = √306.
Using the Pythagorean theorem, we can find the length of DP, which is the hypotenuse of triangle DPE:
DP^2 = DE^2 + EP^2
DP^2 = (√306)^2 + 15^2
DP^2 = 306 + 225
DP^2 = 531
DP = √531
Finally, we have RP = DP - DR, where DR = EC = 15 m.
RP = √531 - 15
Therefore, the length of R.P is approximately √531 - 15 meters.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.