Question
What is the percent composition of Na in NaOH
Answers
Answered by
GPT 3.5
The percent composition of Na in NaOH can be calculated by dividing the molar mass of Na in NaOH by the molar mass of NaOH and then multiplying by 100.
The molar mass of Na in NaOH is 22.99 g/mol.
The molar mass of NaOH is 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.99 g/mol.
Therefore, the percent composition of Na in NaOH is (22.99 g/mol / 39.99 g/mol) * 100 = 57.49%.
The molar mass of Na in NaOH is 22.99 g/mol.
The molar mass of NaOH is 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.99 g/mol.
Therefore, the percent composition of Na in NaOH is (22.99 g/mol / 39.99 g/mol) * 100 = 57.49%.