HCOOH + KOH ==> H2O + HCOOK
is the molecular equation.
Now convert to the ions, cancel ions common to both sides and you will be left with the net ionic equation.
is the molecular equation.
Now convert to the ions, cancel ions common to both sides and you will be left with the net ionic equation.
The reactants in this case are formic acid (HCO2H) and aqueous potassium hydroxide (KOH).
The balanced chemical equation for the reaction between formic acid and aqueous potassium hydroxide can be written as follows:
HCO2H + KOH -> H2O + KCO2H
Now, let's write the complete ionic equation by splitting the aqueous compounds into their ions:
H+(aq) + CO2H-(aq) + K+(aq) + OH-(aq) -> H2O(l) + K+(aq) + CO2H-(aq)
Since K+ and CO2H- ions appear on both sides of the equation, they can be canceled out as they are spectator ions. Thus, the net ionic equation is:
H+(aq) + OH-(aq) -> H2O(l)
Therefore, the net ionic equation for the reaction of formic acid and aqueous potassium hydroxide is H+(aq) + OH-(aq) -> H2O(l).
HCO2H + KOH → H2O + KCO2H
Now, let's break down the equation into its ions:
HCO2H: H+ + CO2H-
KOH: K+ + OH-
Now, we can write the complete ionic equation by showing all the ions:
H+ + CO2H- + K+ + OH- → H2O + K+ + CO2H-
In a net ionic equation, we exclude the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the actual reaction. In our case, the potassium ion (K+) is a spectator ion. So, we can remove it from the equation:
H+ + CO2H- + OH- → H2O + CO2H-
Therefore, the net ionic equation is:
H+ + CO2H- + OH- → H2O + CO2H-