A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center, as shown in the figure below. The linear speed of a passenger on the rim is constant and equal to 6.60 m/s.
What is the magnitude of the passenger's acceleration as she passes through the lowest point in her circular motion?
What is the magnitude of the passenger's acceleration as she passes through the highest point in her circular motion?
How much time does it take the Ferris wheel to make one revolution?
The linear speed is 6.6m/s. Determine the circumference of the wheel and how long it take the wheel to make a revolution, i.e., the wheel's angular velocity. Then use angular acceleration a=v^2/r.
The acceleration going up should be some kind of difference and the accel. coming down should be a sum. I'll let you figure it out.
2 answers