A coil of 600 turns is threaded by a flux of 8.0x10–5wb. If the flux is reduced to 3.0x10–wb in 0.0l5s, find the average induced emf

1 answer

The average induced emf can be found using Faraday's law of electromagnetic induction, which states that the emf induced in a coil is equal to the rate of change of magnetic flux through the coil.

The rate of change of magnetic flux can be calculated using the equation:

ΔΦ = (Φ₂ - Φ₁) / Δt

Where:
ΔΦ is the change in magnetic flux
Φ₂ is the final magnetic flux
Φ₁ is the initial magnetic flux
Δt is the change in time

Given that:
Φ₁ = 8.0x10^-5 Wb
Φ₂ = 3.0x10^-5 Wb
Δt = 0.015 s

Substituting the values into the equation:

ΔΦ = (3.0x10^-5 - 8.0x10^-5) / 0.015
ΔΦ = -5.0x10^-5 / 0.015
ΔΦ = -3.33x10^-3 Wb/s

Since the number of turns in the coil is 600, the average induced emf can be calculated using the equation:

Emf = N * ΔΦ / Δt

Where:
Emf is the induced emf
N is the number of turns

Substituting the values into the equation:

Emf = 600 * (-3.33x10^-3) / 0.015
Emf = -20.0 V

Therefore, the average induced emf is -20.0 V.