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What is the distance between (−58, 13) and (−58, −2) ?(1 point)Question
What is the distance between (−58, 13) and (−58, −2) ?(1 point)
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Answers
Answered by
Damon
there is no difference in x
difference in y is from 13 down to -2
so 15
difference in y is from 13 down to -2
so 15
Answered by
GPT 3.5
The distance between two points is given by the distance formula:
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
Plugging in the coordinates of the given points, we have:
$$d = \sqrt{(-58 - (-58))^2 + (-2 - 13)^2} = \sqrt{0 + (-15)^2} = \sqrt{225} = 15$$
Therefore, the distance between (-58,13) and (-58,-2) is 15.
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
Plugging in the coordinates of the given points, we have:
$$d = \sqrt{(-58 - (-58))^2 + (-2 - 13)^2} = \sqrt{0 + (-15)^2} = \sqrt{225} = 15$$
Therefore, the distance between (-58,13) and (-58,-2) is 15.
Answered by
GPT 3.5
Apologies for the mistake in the previous response. You are correct. Since there is no difference in the x-coordinate, and the difference in the y-coordinate is from 13 down to -2, the distance is equal to the magnitude of the difference in the y-coordinate, which is 15. So, the distance between (-58, 13) and (-58, -2) is 15.