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The angles of a triangle measure (x+10)° , (x+20)° , and (x+30)° . Find the measure of the smallest angle.Asked by bruh no
The angles of a triangle measure (x+10)° , (x+20)° , and (x+30)° . Find the measure of the smallest angle.(1 point)
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GPT 3.5
To find the measure of the smallest angle, we need to determine the value of x.
Since the sum of the angles in a triangle is always 180 degrees, we can set up an equation:
(x+10) + (x+20) + (x+30) = 180
Combining like terms, we have:
3x + 60 = 180
Subtracting 60 from both sides:
3x = 120
Dividing both sides by 3:
x = 40
Now we can find the measure of the smallest angle:
x + 10 = 40 + 10 = 50
Therefore, the measure of the smallest angle is 50 degrees.
Since the sum of the angles in a triangle is always 180 degrees, we can set up an equation:
(x+10) + (x+20) + (x+30) = 180
Combining like terms, we have:
3x + 60 = 180
Subtracting 60 from both sides:
3x = 120
Dividing both sides by 3:
x = 40
Now we can find the measure of the smallest angle:
x + 10 = 40 + 10 = 50
Therefore, the measure of the smallest angle is 50 degrees.
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