Asked by Robert C
A person on horseback moves according to the velocity-versus-time graph shown in Figure 2-32. (The vertical axis is marked in increments of 1 m/s and the horizontal axis is marked in increments of 7 s.) Find the displacement of the person for each of the segments A, B, and C.
sA =
sB =
sC =
A has to coordinates Velocity 1m/s time 14s
B has the coordinates V = 3m/s
time 21s
C has the coordinates V = 1m/s
time 35s
sA =
sB =
sC =
A has to coordinates Velocity 1m/s time 14s
B has the coordinates V = 3m/s
time 21s
C has the coordinates V = 1m/s
time 35s
Answers
Answered by
bobpursley
It is really pretty simple: Displacement is the area under the velocity-time graph
(remember in the 5th grade...distance=velocity*time?)
So count the squares under the graph, each one is (1m/s*7sec=7m)
(remember in the 5th grade...distance=velocity*time?)
So count the squares under the graph, each one is (1m/s*7sec=7m)