2 Find the axis of symmetry, the vertex, and

Question

the y-intercept for the following quadratic
equation:
𝑦 = 𝑥squared + 2𝑥 − 2

Answer 1

To find the axis of symmetry, we can use the formula:

𝑥 = -𝑏/2𝑎

In this case, 𝑎 = 1 and 𝑏 = 2. Plugging these values into the formula, we get:

𝑥 = -2/ (2*1)
𝑥 = -1

So the axis of symmetry is 𝑥 = -1.

To find the vertex, we can substitute the value of 𝑥 into the equation:

𝑦 = (-1)^2 + 2(-1) - 2
𝑦 = 1 - 2 - 2
𝑦 = -3

So the vertex is (-1,-3).

To find the y-intercept, we can substitute 𝑥 = 0 into the equation:

𝑦 = (0)^2 + 2(0) - 2
𝑦 = 0 - 0 - 2
𝑦 = -2

So the y-intercept is (0,-2).