First, solve one of the equations for one variable in terms of the other. We can solve the second equation for y:
3x - y = 0
-y = -3x
y = 3x
Now substitute this expression for y into the first equation:
4x - 14 = -y
4x - 14 = -(3x)
4x - 14 = -3x
7x = 14
x = 2
Substitute the value of x back into the second equation to solve for y:
3x - y = 0
3(2) - y = 0
6 - y = 0
y = 6
Therefore, the solution to the system is x = 2 and y = 6.
Solve the following system by the substitution method.
4x−14=−y
3x−y=0
(1 point)
$$
1 answer
2 answers