The kinetic energy of a 25-gram bullet traveling at 500 m/s is what

Answer 1

The kinetic energy of an object is given by the formula:

Kinetic energy = 0.5 * mass * velocity^2

Given:
Mass of bullet = 25 grams = 0.025 kg
Velocity of bullet = 500 m/s

Plugging in these values into the formula, we get:

Kinetic energy = 0.5 * 0.025 kg * (500 m/s)^2
= 0.5 * 0.025 kg * 250,000 m^2/s^2
= 3,125 joules

Therefore, the kinetic energy of the bullet is 3,125 joules.