25g of a sample of ferrous sulphate was dissolved in water containing dilute h2s04 and the volume made up to one litre. 25ml of this solution required 20ml of this solution required 20ml of n/10 kmn04 solution for complete oxidation. Calculate the percentage of f2s047h20 in the sample
My calculation
0.002x1000ml x293g.mol/25ml = 23.44
23.44/25g x 100% = 93.76%
The right answer 88.96%
Please Damon solve it for me again
1 answer
recheck you mol mass, in my head I get about 278g/mol
0 answers