25g of a sample of ferrous sulphate was dissolved in water containing dilute h2s04 and the volume made up to one litre. 25ml of this solution required 20ml of N/10 kmn04 solution for complete oxidation. Calculate the percentage of fes047h20 in the sample
The answer 88.96%
My calculation
0.02 x 0.1= 0.002
0.002 x 1000ml x 293g/mol / 25ml = 23.44
23.44/ 25g x 100 = 93.76% The wrong answer.
Steve wants you to solve it for me.