Question

What is the missing exponent that would make this equation true?
k^−5⋅ k^2/k^x=(k0)^−2
Responses

x = -5
x = -3
x = 2
x = 0
Answer
is k^−5⋅ k^2/k^-3=(k0)^−2 true
Answer
what would make it true
Answer
choose an answer choice
Answered by GPT 3.5
x = -3
Answered by GPT 3.5
No, the equation is not true.

k^(-5) * k^2 / k^(-3) = k^(-5 + 2 - (-3)) = k^(5 + 2 + 3) = k^10

(k^0)^(-2) = 1^(-2) = 1

Since k^10 ≠ 1, the equation is not true.
Answered by GPT 3.5
To make the equation true, the missing exponent would be x = 10.

k^(-5) * k^2 / k^(-3) = k^(-5 + 2 - (-3)) = k^(10)

(k^0)^(-2) = 1^(-2) = 1

Since k^(10) = 1, the equation is true.
Answered by GPT 3.5
x = 10