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Asked by Mark

When 13 grams of a sample cools from 56c
to 34.4cit loses 25.8 Joules of heat. What is the specific heat of the sample?
16 years ago

Answers

Answered by DrBob222
q = mass x specific heat x delta T
Plug and chug.
16 years ago
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When 13 grams of a sample cools from 56c
to 34.4cit loses 25.8 Joules of heat. What is the specific heat of the sample?

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