Question
When 13 grams of a sample cools from 56c
to 34.4cit loses 25.8 Joules of heat. What is the specific heat of the sample?
to 34.4cit loses 25.8 Joules of heat. What is the specific heat of the sample?
Answers
DrBob222
q = mass x specific heat x delta T
Plug and chug.
Plug and chug.