BCE~JKL. If m angle B = 89 deg m angle C = 13 deg and ∠E = 78 deg what is m∠J?

Answer 1

Since the angles of a triangle add up to 180 degrees, we can find m∠J by subtracting the sum of the known angles from 180 degrees.

m∠J = 180 - m∠B - m∠C - m∠E
m∠J = 180 - 89 - 13 - 78
m∠J = 180 - 180
m∠J = 0

Therefore, m∠J = 0 degrees.

Answer 2

wrong

Answer 3

Apologies for the mistake. Let's try again.

In triangle BCE, the sum of the angles is 180 degrees.

We know that:

m∠B = 89 degrees
m∠C = 13 degrees
m∠E = 78 degrees

To find m∠J, we need to subtract the sum of these angles from 180 degrees:

m∠J = 180 - (m∠B + m∠C + m∠E)
m∠J = 180 - (89 + 13 + 78)
m∠J = 180 - 180
m∠J = 0

Therefore, m∠J = 0 degrees.

Answer 4

thats not the answer

Answer 5

Apologies for the confusion. Let's try again.

In triangle BCE, the sum of the angles is 180 degrees.

We know that:

m∠B = 89 degrees
m∠C = 13 degrees
m∠E = 78 degrees

To find m∠J, we need to subtract the sum of these angles from 180 degrees:

m∠J = 180 - (m∠B + m∠C + m∠E)
m∠J = 180 - (89 + 13 + 78)
m∠J = 180 - 180
m∠J = 0

Therefore, m∠J = 0 degrees.

I apologize for the mistake again. Let's recalculate.

The angles around a point add up to 360 degrees. In triangle BCE, we know that m∠B + m∠C + m∠E + m∠J + m∠K + m∠L = 360.

We are given that:
m∠B = 89 degrees
m∠C = 13 degrees
m∠E = 78 degrees

We need to find m∠J.

By substituting the given values into the equation, we have:

89 + 13 + 78 + m∠J + m∠K + m∠L = 360

Simplifying the equation:

180 + m∠J + m∠K + m∠L = 360

Now, we can isolate m∠J:

m∠J = 360 - 180 - m∠K - m∠L
m∠J = 180 - m∠K - m∠L

Therefore, the value of m∠J is 180 minus the sum of angles m∠K and m∠L. The information provided doesn't give us enough information to determine the specific value of m∠J.

Answer 6

for anyone still wondering its 89