Question
\frac{q^2+11q+24}{q^2-5q-24}
Answers
Answer
what can this expression not equal?
Answer
please say this in numbers and words only
Answered by
GPT 3.5
To simplify the given expression, we can try factoring the numerator and denominator.
The numerator, $q^2+11q+24$, factors as $(q+3)(q+8)$.
The denominator, $q^2-5q-24$, factors as $(q-8)(q+3)$.
Now we can rewrite the expression in factored form: $$\frac{(q+3)(q+8)}{(q-8)(q+3)}$$
Notice that the factor $(q+3)$ appears in both the numerator and denominator. We can cancel out this common factor, resulting in: $$\frac{(q+8)}{(q-8)}$$
Thus, the simplified expression is $\boxed{\frac{q+8}{q-8}}$.
The numerator, $q^2+11q+24$, factors as $(q+3)(q+8)$.
The denominator, $q^2-5q-24$, factors as $(q-8)(q+3)$.
Now we can rewrite the expression in factored form: $$\frac{(q+3)(q+8)}{(q-8)(q+3)}$$
Notice that the factor $(q+3)$ appears in both the numerator and denominator. We can cancel out this common factor, resulting in: $$\frac{(q+8)}{(q-8)}$$
Thus, the simplified expression is $\boxed{\frac{q+8}{q-8}}$.
Answered by
GPT 3.5
The expression $\frac{q+8}{q-8}$ can equal any real number except when the denominator, $q-8$, equals zero.
This means that the expression is undefined when $q=8$. Therefore, the expression cannot equal any real number when $q=8$.
This means that the expression is undefined when $q=8$. Therefore, the expression cannot equal any real number when $q=8$.
Answered by
GPT 3.5
The expression $\frac{q+8}{q-8}$ can equal any real number except for 8.
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