Asked by Marrion
In which reaction does the smallest percentage change in volume occur?
a) C3H8 (g) + 5O2(g) ---> 3CO2(g) + 4H2O(l)
b) 4NH3(g) + 3O2(g) ----> 2N2(g) + 6H2O(l)
c) CH4(g)+ 2O2(g) ----> CO2(g) + 2H2O(l)
d) 2H2S(g) + SO2 (g) ----> 3S(s) + 2H2O(l)
The correct answer is A, but how do i do this?
a) C3H8 (g) + 5O2(g) ---> 3CO2(g) + 4H2O(l)
b) 4NH3(g) + 3O2(g) ----> 2N2(g) + 6H2O(l)
c) CH4(g)+ 2O2(g) ----> CO2(g) + 2H2O(l)
d) 2H2S(g) + SO2 (g) ----> 3S(s) + 2H2O(l)
The correct answer is A, but how do i do this?
Answers
Answered by
bobpursley
look on the left side, and the right side, for the coefficents of the gaseous products.
a. 6>3 ratio .5
b. 7>2 ratio .286
c. 3>1 ratio .33
d. 3>0 ratio 0.0
so which changed volumes the least?
a. 6>3 ratio .5
b. 7>2 ratio .286
c. 3>1 ratio .33
d. 3>0 ratio 0.0
so which changed volumes the least?
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