Question
The figure below shows an object of mass M = 1,276 g. It is free to move along a horizontal, frictionless surface. This object is further connected to a second object with a mass of m = 1,362 g by means of a massless string that extends around a massless, frictionless pulley. Find the tension of the massless string.
The figure:
M is placed on a table/surface where m is hanging down with the string attaching it to M.
Thank you.
The figure:
M is placed on a table/surface where m is hanging down with the string attaching it to M.
Thank you.
Answers
so m is pulling M.
force equation:\
mg=(M+m)a solve for a.
Then, tension = force pulling M or M*a
force equation:\
mg=(M+m)a solve for a.
Then, tension = force pulling M or M*a
from the FBDs wouldnt u get
for M:
Fy = N-WM=Ma
Fx=T=Ma
for m:
Fy= T-Wm=ma
Fx= T-W=ma
then solve for a in M of Fx
and sub a into m of Fx to get T?
for M:
Fy = N-WM=Ma
Fx=T=Ma
for m:
Fy= T-Wm=ma
Fx= T-W=ma
then solve for a in M of Fx
and sub a into m of Fx to get T?
Sorry i see the mistake I made
for m the acceleration would be negative since its moving down
for m the acceleration would be negative since its moving down
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