3(3y + 9) []\lessequal; 2y + 13

Answer 1

To solve the inequality, we need to distribute the 3 on the left side of the inequality sign:

3(3y + 9) ≤ 2y + 13.

Now, expand:

9y + 27 ≤ 2y + 13.

Next, we gather like terms by subtracting 2y from both sides:

9y - 2y + 27 ≤ 13.

Simplifying the left side:

7y + 27 ≤ 13.

Subtract 27 from both sides:

7y ≤ -14.

Lastly, divide both sides by 7:

y ≤ -2.

Therefore, the solution to the inequality is y ≤ -2.