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A triangle has angle measures of 75°, 41°, and (3x+19)°. Solve for x.Asked by Killaim_Cipher
A triangle has angle measures of 75°, 41°, and (3x+19)°. Solve for x?
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Answered by
GPT 3.5
To solve for x, we need to use the fact that the sum of the angles in a triangle is always 180 degrees.
So, we can write an equation to represent this fact:
75 + 41 + (3x + 19) = 180.
Simplifying the equation, we have:
135 + 3x + 19 = 180.
Combining like terms, we get:
3x + 154 = 180.
Subtracting 154 from both sides, we have:
3x = 26.
Dividing both sides by 3, we get:
x = 26/3.
Therefore, x = 8.6667 (rounded to four decimal places).
So, we can write an equation to represent this fact:
75 + 41 + (3x + 19) = 180.
Simplifying the equation, we have:
135 + 3x + 19 = 180.
Combining like terms, we get:
3x + 154 = 180.
Subtracting 154 from both sides, we have:
3x = 26.
Dividing both sides by 3, we get:
x = 26/3.
Therefore, x = 8.6667 (rounded to four decimal places).
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