Asked by Suchi
An executive flew in the corporate to a meeting in a city 1500 km away. After traveling the same amount of time on the return flight, the pilot mentioned that they still had 300 km to go. The airspeed of the plane was 600 km/h. How fast was the wind blowing (assuming that the wind direction was parallel to the flight path and constant all day.)?
Answers
Answered by
Suchi
Please show work...
Answered by
MathMate
Please show us your thinking and problems if you have any.
Answered by
Suchi
well i got this so far:
total d = 1500 km
total time to get to destination = t(subscript)1 which is also equal to time taken to travel 1200 km back home.
Then I used d=rt formula,
I tried 1500 = 600 (t(subscript)1)
t(subscript)1=2.5hrs
2.5hrs =1200 km on return flight
1200r (2.5)
r = 480km/h
1500 = 480 t(subscript)2.
that meant 600 - 480 would be 120 km/h but when i checked my answer, it said that the answer is 66 2/3 km/h... i am confused... PLZ HELP!!!
total d = 1500 km
total time to get to destination = t(subscript)1 which is also equal to time taken to travel 1200 km back home.
Then I used d=rt formula,
I tried 1500 = 600 (t(subscript)1)
t(subscript)1=2.5hrs
2.5hrs =1200 km on return flight
1200r (2.5)
r = 480km/h
1500 = 480 t(subscript)2.
that meant 600 - 480 would be 120 km/h but when i checked my answer, it said that the answer is 66 2/3 km/h... i am confused... PLZ HELP!!!
Answered by
MathMate
66 2/3 is correct.
You would want to denote the unknown by a variable name, say v for velocity of wind.
The question stated that the time to travel 1500 km (with the wind) is the same as that required to travel 1200 km back (against the wind).
Can you express the previous paragraph in terms of the wind velocity, v, the air speed of 600 km/h and the distances 1500 and 1200?
If you can, solve it and you should get your required answer of 66 2/3. If not, post again.
You would want to denote the unknown by a variable name, say v for velocity of wind.
The question stated that the time to travel 1500 km (with the wind) is the same as that required to travel 1200 km back (against the wind).
Can you express the previous paragraph in terms of the wind velocity, v, the air speed of 600 km/h and the distances 1500 and 1200?
If you can, solve it and you should get your required answer of 66 2/3. If not, post again.
Answered by
Suchi
sry, I don't understand :[...
Answered by
MathMate
"The question stated that the time to travel 1500 km (with the wind) is the same as that required to travel 1200 km back (against the wind). "
Time to traval to destination
= Distance / velocity
= 1500 / (600 + v)
Time to return (part of the way)
= Dostance / velocity
= ...
Equate the two, since they are equal and solve for v.
Can you take it from here?
Time to traval to destination
= Distance / velocity
= 1500 / (600 + v)
Time to return (part of the way)
= Dostance / velocity
= ...
Equate the two, since they are equal and solve for v.
Can you take it from here?
Answered by
Suchi
Oh... hold opn, let me try it!!! if I don't get it, I'll try to post what I did! if i do, then thanx!!
Answered by
Suchi
THANK YOU SO MUCH!!!!
Answered by
MathMate
I am sure you can. If not, post anyway. If I don't reply tonight, it will be tomorrow.
There are no AI answers yet. The ability to request AI answers is coming soon!