The sides of a triangular path measure 7 m, 9 m, and 11 m. Find the perimeter of a similar triangle in which the shortest side has a length of 21 meters. (1 point)

Question

81 m
33 m
21 m
27 m

Answer 1

To find the perimeter of a similar triangle, we can use the concept of proportionality between corresponding sides.

In this case, we know that the ratio of the corresponding sides of the two triangles must be the same. Let's call this ratio "k."

The corresponding sides of the original triangle are 7 m, 9 m, and 11 m.
The corresponding sides of the similar triangle are 21 m, x, and y (which we need to find).

To find the value of "k," we can set up the following proportion:
7/21 = 9/x = 11/y

Solving this proportion, we find that x = (21 * 9) / 7 = 27 m and y = (21 * 11) / 7 = 33 m.

Now we can find the perimeter of the similar triangle by adding up the lengths of all three sides:
Perimeter = 21 + 27 + 33 = 81 m

Therefore, the correct answer is 81 m.