The sides of a triangular path measure 7 m, 9 m, and 11 m. Find the perimeter of a similar triangle in which the shortest side has a length of 21 meters. (1 point)

Question

81 m
33 m
21 m
27 m

Answer 1

To find the perimeter of a similar triangle, we can use the fact that corresponding sides of similar triangles are proportional.

In this case, since we are increasing the length of the shortest side from 7 m to 21 m, we need to find the scale factor by dividing the new length by the original length:
21 m / 7 m = 3

Now, we can find the lengths of the other two sides of the similar triangle by multiplying the scale factor by their original lengths:
9 m * 3 = 27 m
11 m * 3 = 33 m

Finally, we can find the perimeter by adding up the lengths of all three sides:
21 m + 27 m + 33 m = 81 m

Therefore, the perimeter of the similar triangle with the shortest side measuring 21 meters is 81 m. Answer: \boxed{81 \, \text{m}}.