Asked by Chan
Hi!Question:Two packing crates of masses m1 = 10.0 kg and m2 = 6.50 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 6.50 kg crate lies on a smooth incline of angle 45.0°. Find the acceleration of the 6.50 kg crate.
_________m/s2 (up the incline)
Find the tension in the string.
_________ N
Thank you so much
_________m/s2 (up the incline)
Find the tension in the string.
_________ N
Thank you so much
Answers
Answered by
bobpursley
I assume the m1 is hanging vertically. This is called an Atwood machine
the force of gravity acts on both, on m1,it is vertical, m1*g
On m2, it is downward,of course, but the component down the plane is m2*g*sinTheta
Net force=totalmass*acceleration
m1*g-m2*gsinTheta=(m1+m2)*a
solve for a.
The tension? at M1,
tension=m1*(g-a)
the force of gravity acts on both, on m1,it is vertical, m1*g
On m2, it is downward,of course, but the component down the plane is m2*g*sinTheta
Net force=totalmass*acceleration
m1*g-m2*gsinTheta=(m1+m2)*a
solve for a.
The tension? at M1,
tension=m1*(g-a)
Answered by
Anonymous
ur dumb
Answered by
bobpursley
AS_HOLES
Answered by
Bobiscool
keep ur head up bob, keep rocking in the free world and DOOTDODOALOOTDOO DOOTDOOT
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