Solve 6 11/12-(2 1/4+3 2/3) do it in parentheses first. show all your steps

1 answer

First, let's solve what's inside the parentheses:

2 1/4 + 3 2/3

To add these mixed numbers, we need to convert them to improper fractions:

2 1/4 = 9/4
3 2/3 = 11/3

Now we can add them:

9/4 + 11/3

To add fractions, we need a common denominator, which in this case is 12.

Converting both fractions to have a denominator of 12:

(9/4) * (3/3) = 27/12
(11/3) * (4/4) = 44/12

Now we can add them:

27/12 + 44/12 = 71/12

This is the result inside the parentheses. Now let's solve the entire expression:

6 11/12 - (71/12)

To subtract fractions, we need a common denominator, which is already 12.

So we can now subtract:

6 - 71/12

To subtract mixed numbers, we need to combine the integer and the fraction parts:

6 = 72/12

Now we can subtract:

72/12 - 71/12 = 1/12

Therefore, the final result is 1/12.
Similar Questions
  1. Solve 6 11/12−(2 1/4+3 2/3). Do the operation in parentheses first. Show all your steps. (2 points)
    1. answers icon 3 answers
  2. Solve 61112−(214+323). Do the operation in parentheses first. Show all your steps. (2 points)
    1. answers icon 1 answer
  3. How do you solve the following:Directions:Factor Can you show me!!! (1) x^2-x-12 (2)x^3+2x^2-3x Here is how I do it. First make
    1. answers icon 0 answers
    1. answers icon 2 answers
more similar questions