Asked by boof
Find the indicated probability.
An archer is able to hit the bull's-eye 53% of the time. If the archer shoots 10 arrows, what is the probability they get exactly 4 bull's-eyes? Assume each shot is independent of the others.
(1 point)
Responses
0.179
0.179
0.0789
0.0789
0.821
0.821
0.0905
0.0905
An archer is able to hit the bull's-eye 53% of the time. If the archer shoots 10 arrows, what is the probability they get exactly 4 bull's-eyes? Assume each shot is independent of the others.
(1 point)
Responses
0.179
0.179
0.0789
0.0789
0.821
0.821
0.0905
0.0905
Answers
There are no human answers yet.
Answered by
GPT 3.5
The probability of hitting the bull's-eye is 53% or 0.53. To find the probability of getting exactly 4 bull's-eyes out of 10 shots, we use the binomial probability formula.
P(X = k) = C(n, k) * p^k * (1-p)^(n-k)
Where:
P(X = k) is the probability of getting exactly k successes
n is the number of trials (in this case, the number of shots)
k is the number of successes (in this case, 4 bull's-eyes)
p is the probability of success (in this case, 0.53)
Using this formula, we plug in the values:
P(X = 4) = C(10, 4) * (0.53)^4 * (1-0.53)^(10-4)
Calculating this gives us:
P(X = 4) = 210 * 0.53^4 * 0.47^6
P(X = 4) ≈ 0.179
So, the probability they get exactly 4 bull's-eyes out of 10 shots is approximately 0.179.
P(X = k) = C(n, k) * p^k * (1-p)^(n-k)
Where:
P(X = k) is the probability of getting exactly k successes
n is the number of trials (in this case, the number of shots)
k is the number of successes (in this case, 4 bull's-eyes)
p is the probability of success (in this case, 0.53)
Using this formula, we plug in the values:
P(X = 4) = C(10, 4) * (0.53)^4 * (1-0.53)^(10-4)
Calculating this gives us:
P(X = 4) = 210 * 0.53^4 * 0.47^6
P(X = 4) ≈ 0.179
So, the probability they get exactly 4 bull's-eyes out of 10 shots is approximately 0.179.
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