In which of the given sets of numbers are all the numbers solutions of 18+2x greater than or equal to 36?

Question

8,7,6
0,3,9,12
9,10,11,12
9,8,7,6

Answer 1

To solve the inequality 18 + 2x ≥ 36, we subtract 18 from both sides to isolate 2x:

2x ≥ 18

Then, we divide both sides by 2:

x ≥ 9

Now we can compare the sets of numbers:

1) 8, 7, 6: None of these numbers is greater than or equal to 9, so it is not a solution.

2) 0, 3, 9, 12: 9 is greater than or equal to 9, so it is a solution.

3) 9, 10, 11, 12: All of these numbers are greater than or equal to 9, so they are solutions.

4) 9, 8, 7, 6: 9 is greater than or equal to 9, so it is a solution.

Therefore, the sets of numbers where all the numbers are solutions of 18 + 2x ≥ 36 are:

2) 0, 3, 9, 12
3) 9, 10, 11, 12
4) 9, 8, 7, 6