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A cyclist passes a race check point at +5.5m/s and then accelerates ata constant rate of +.55 m/s^2. The cyclist forgot to check in at the check point, and after 20s turns back around to head back. How far did the cylist move from the check point to the point of turning back?
A cyclist passes a race check point at +5.5m/s and then accelerates ata constant rate of +.55 m/s^2. The cyclist forgot to check in at the check point, and after 20s turns back around to head back. How far did the cylist move from the check point to the point of turning back?
Answers
Answered by
drwls
After 20 s, the speed increased from 5.5 m/s to
5.5 m/s + 0.55*20 = 11.5 m/s
The average speed during the 20s was
(11.5 + 5.5)/2 = 8.5 m/s
Multiply that by 20 s for the distance travelled.
5.5 m/s + 0.55*20 = 11.5 m/s
The average speed during the 20s was
(11.5 + 5.5)/2 = 8.5 m/s
Multiply that by 20 s for the distance travelled.
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