Asked by sally
                The acceleration of a certain rocket is given by ax=bt where b is positive constant, find the position and velocity at t=5.0s if Xo=0 and Vo=0 and b=3.0m/s^3?
            
            
        Answers
                    Answered by
            MathMate
            
    I assume in ax=bt, x is a subscript and not a variable.  'a' will be used from here on.
Since initial conditions are all known, the function X(t) can be found by integrations.
b=3.0 m/s³
a(t) = bt
V(t) = ∫a(t) + C1
= (b/2)t² + C1
since V(0)=Vo=0, C1=0, therefore
V(t) = (b/2)t²
X(t) = ∫V(t) + C2
= (b/6)t³ + C2
Since X(0)=Xo=0, C2=0, therefore
X(t)=(b/6)t³
Calculate X(5).
    
Since initial conditions are all known, the function X(t) can be found by integrations.
b=3.0 m/s³
a(t) = bt
V(t) = ∫a(t) + C1
= (b/2)t² + C1
since V(0)=Vo=0, C1=0, therefore
V(t) = (b/2)t²
X(t) = ∫V(t) + C2
= (b/6)t³ + C2
Since X(0)=Xo=0, C2=0, therefore
X(t)=(b/6)t³
Calculate X(5).
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