The point-slope form of a linear equation is given by y - y₁ = m(x - x₁), where (x₁, y₁) is the given point and m is the given slope.
Plugging in the values, we get:
y - (-1) = (6/7)(x - 3)
Simplifying the equation:
y + 1 = (6/7)(x - 3)
Multiplying through by 7 to clear the fraction:
7(y + 1) = 6(x - 3)
Distributing on both sides:
7y + 7 = 6x - 18
Re-arranging the terms:
6x - 7y = 25
So, the equation of the line with slope 6/7 and passing through the point (3, -1) is 6x - 7y = 25.
Find an equation of the line having the given slope and containing the given point.
m = 6/7, (3, -1)
1 answer