a^5 − bc + 4a ÷ c when a = 2, b = 3, and c

In order to solve the expression "a^5 - bc + 4a ÷ c" when a = 2, b = 3, and c is not given, we need to substitute the values of a, b, and c into the expression and then simplify it.

Substituting the values given, the expression becomes:

2^5 - 3c + 4(2) ÷ c

Simplifying further using the order of operations (BIDMAS/PEMDAS):

= 32 - 3c + 8 ÷ c

We cannot simplify it further without knowing the value of c.

c = to 8

Great! Now that we know c is 8, let's substitute that value into the expression:

2^5 - 3(8) + 4(2) ÷ 8

Using the order of operations:

= 32 - 24 + 8 ÷ 8

= 32 - 24 + 1

= 9

So, when a = 2, b = 3, and c = 8, the expression "a^5 - bc + 4a ÷ c" equals 9.