Asked by math is pointless
for each function, find an equasion for the inverse. then use composition to verify that the equasion you wrote is the inverse.
g(x)=-6x+5
please explain how you got the answer
g(x)=-6x+5
please explain how you got the answer
Answers
Answered by
jim
An inverse just undoes what the original function did, so you can get it by doing the opposite of what the original functtion did, in reverse order.
g(x) tells you: multiply by -6, then add 5.
Its inverse will tell you: subtract 5, then divide by -6.
Example: g(2) = 2*-6 + 5 = -7.
Inverse (call it h()):
h(-7) = (-7-5)/-6 = 2
so h(x) is going to look like (x-5)/-6.
Composition means finding h(g(x)); in other words write out g(x) in full instead of x and then apply h(x) to it, and if we're right, the whole mess should come back to be equal to x, where we started.
g(x)=-6x+5
h(g(x)) = ((-6x+5)-5)/-6
Does that get back to plain old x?
g(x) tells you: multiply by -6, then add 5.
Its inverse will tell you: subtract 5, then divide by -6.
Example: g(2) = 2*-6 + 5 = -7.
Inverse (call it h()):
h(-7) = (-7-5)/-6 = 2
so h(x) is going to look like (x-5)/-6.
Composition means finding h(g(x)); in other words write out g(x) in full instead of x and then apply h(x) to it, and if we're right, the whole mess should come back to be equal to x, where we started.
g(x)=-6x+5
h(g(x)) = ((-6x+5)-5)/-6
Does that get back to plain old x?
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