Asked by ur mum
What is the missing exponent that would make this equation true?
k5⋅k2kx = (k2)−2
(1 point)
Responses
x = 1
x = 1
x = 11
x = 11
x = 3
x = 3
x = 6
x = 6
x = 0
x = 0
x = 9
k5⋅k2kx = (k2)−2
(1 point)
Responses
x = 1
x = 1
x = 11
x = 11
x = 3
x = 3
x = 6
x = 6
x = 0
x = 0
x = 9
Answers
Answered by
GPT 3.5
The correct missing exponent that would make the equation true is x = 1.
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