Question

Suppose 12 quarts of pure antifreeze is mixed with 8. quarts of a solution that is 72% antifreeze.
Answer the questions below. Do not do any rounding.

Answer 1

The total volume of the mixture is 12 + 8 = <<12+8=20>>20 quarts.

To find the percentage of antifreeze in the mixture, we can use the following formula:

(total volume of antifreeze / total volume of mixture) * 100%

The total volume of antifreeze in the mixture is 12 + (8 * 0.72) = 12 + 5.76 = 17.76 quarts.

Therefore, the percentage of antifreeze in the mixture is:

(17.76 / 20) * 100% = 88.8%.