Two angles <1 and <2 in a diagram are complementary. If m <2 = 26° what equation can you write to solve for m<1

Answer 1

Since <1 and <2 are complementary angles, their measures add up to 90 degrees. Therefore, we can write the equation:

m<1 + m<2 = 90

Substituting m<2 = 26 degrees, the equation becomes:

m<1 + 26 = 90

To solve for m<1, we can subtract 26 from both sides of the equation:

m<1 = 90 - 26

Therefore, the equation to solve for m<1 is:

m<1 = 64

Answer 2

In a diagram < 3 and <5 are vertical angles and <4 is a supplementary angle with <5 if m < 3= 67° what equation can u write to solve for m < 4

Answer 3

Vertical angles are congruent, so m<3 = m<5. Additionally, supplementary angles add up to 180 degrees.

In this case, we can write the equation:

m<3 + m<4 = 180

Now, we substitute m<3 = 67 degrees:

67 + m<4 = 180

To solve for m<4, we need to isolate it. We subtract 67 from both sides of the equation:

m<4 = 180 - 67

So, the equation to solve for m<4 is:

m<4 = 113

Answer 4

Together the measures of <B < C <D equal 180°
the angles have the following measures: m<B = 25°, m<C = (3x)° and m <D - (3x + 5)°
what are the measurs of <C and <D

Answer 5

Since the measures of <B, <C, and <D add up to 180 degrees, we can write the equation:

m<B + m<C + m<D = 180

Substituting the given values, the equation becomes:

25 + 3x + (3x + 5) = 180

Simplifying the equation, we have:

25 + 6x + 5 = 180

Combining like terms:

30 + 6x = 180

To solve for x, we need to isolate it. We subtract 30 from both sides of the equation:

6x = 150

Dividing both sides by 6:

x = 25

Now that we have the value of x, we can substitute it back into the expressions for m<C and m<D:

m<C = 3x = 3(25) = 75

m<D = 3x + 5 = 3(25) + 5 = 75 + 5 = 80

Therefore, the measures of <C and <D are 75° and 80°, respectively.

Answer 6

In the diagram m<A= (4x- 10)° and m <D= (2x + 22)°
What is the measure of <D

Answer 7

The measure of <D is given by m<D = (2x + 22)°.

However, to determine the exact measure of <D, we need to know the value of x. Without that information, we cannot find the specific measure of <D.