rosalyn and naomi left their homes, which are 330 miles apart, and drove straight towards each other. it took 3 hours for the two to meet. If naomi's speed was 10 mph slower than rosalyn's speed, what was rosalyn's speed?

Answer 1

Let's assume Rosalyn's speed is x mph.
Naomi's speed is 10 mph slower, so Naomi's speed is (x - 10) mph.
Since they traveled towards each other for 3 hours, the total distance covered is the sum of their distances.
Rosalyn covered a distance of 3x miles.
Naomi covered a distance of 3(x - 10) miles.
The sum of their distances is 330 miles:
3x + 3(x - 10) = 330
3x + 3x - 30 = 330
6x - 30 = 330
6x = 360
x = 360/6
x = <<60=60>>60 mph.
Therefore, Rosalyn's speed was 60 mph. Answer: \boxed{60}.