Vertical angle.

angle 1: x+16
angle 2: 4x-5
Use the properties of vertical angles to find the value of x
a.3
b.5
c.7
d.9

9 answers

Vertical angles are congruent, meaning that they have the same measure. In this case, we can set the two angles equal to each other and solve for x:

x + 16 = 4x - 5

Subtract x from both sides:
16 = 3x - 5

Add 5 to both sides:
21 = 3x

Divide both sides by 3:
x = 7

Therefore, the value of x is 7. Therefore, the correct answer is c.7.
follow up to the previous question:
what is the measure of angle a?
To find the measure of angle a, we substitute the value of x into equation (angle 1: x + 16):

angle 1: 7 + 16
angle 1: 23

The measure of angle a is 23 degrees.
23 is not an option.
Vertical angle.
angle 1: x+16
angle 2: 4x-5
Use the properties of vertical angles to find the value of x
a.3
b.5
c.7
d.9
-----
follow up to the previous question:
what is the measure of angle a?
a.157
b.159
c.161
d.163
I apologize for the previous incorrect response.

Given that angle 1 is x + 16, and angle 2 is 4x - 5, we can set up the equation:

x + 16 = 4x - 5

Subtract x from both sides:
16 = 3x - 5

Add 5 to both sides:
21 = 3x

Divide both sides by 3:
x = 7

Now that we have found the value of x, we can substitute it back into angle 1 and find the measure of angle a:

angle 1 = x + 16 = 7 + 16 = 23

The measure of angle a is 23 degrees.

Therefore, the correct answer is not included in the list of options you provided (a. 157, b. 159, c. 161, d. 163).
then pick the closest answer
If the measure of angle a is 23 degrees, the closest answer from the given options would be (c) 161 degrees.
you got question 1 correctly but question two is 157.
Apologies for the incorrect response earlier.

If the measure of angle 1 is 23 degrees, the measure of angle 2 (vertical angle) will also be 23 degrees.

To find the measure of angle a, we add the measures of angle 1 and angle 2:

angle a = angle 1 + angle 2 = 23 + 23 = 46 degrees

Therefore, the correct answer for the measure of angle a is (a) 157 degrees is incorrect.
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