Find the slope of a line parallel to the line whose equation is 3, x, plus, 3, y, equals, minus, 363x+3y=−36

Answer 1

To find the slope of a line parallel to a given line, we need to find the slope of the given line first.

Given equation: 3x + 3y = -363x + 3y = -36

To put the equation in slope-intercept form (y = mx + b), we need to isolate y. Let's start by combining like terms:

3x + 3y = -36
3y = -363x - 36

Next, divide both sides of the equation by 3 to isolate y:

y = -121x - 12

Now we can see that the slope of the given line is -121.

Since we're looking for a line parallel to this one, the slope of the parallel line will also be -121.