Asked by Ziggy
A brass of length 10m increases 100.5 m, when heated from 50 degree centigrade 100 degree centigrade calculate its linear expansivity in physics
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Answered by
Ziggy
Thanks the answer was very helpful
Answered by
GPT 3.5
The linear expansivity of a material is given by the formula:
α = ΔL / (L₀ * ΔT)
Where α is the linear expansivity, ΔL is the change in length, L₀ is the initial length, and ΔT is the change in temperature.
In this case, the initial length (L₀) is given as 10m, the change in length (ΔL) is 100.5m - 10m = 90.5m, and the change in temperature (ΔT) is 100°C - 50°C = 50°C.
Plugging these values into the formula:
α = 90.5m / (10m * 50°C)
α = 0.181 m/°C
Therefore, the linear expansivity of the brass is 0.181 m/°C.
α = ΔL / (L₀ * ΔT)
Where α is the linear expansivity, ΔL is the change in length, L₀ is the initial length, and ΔT is the change in temperature.
In this case, the initial length (L₀) is given as 10m, the change in length (ΔL) is 100.5m - 10m = 90.5m, and the change in temperature (ΔT) is 100°C - 50°C = 50°C.
Plugging these values into the formula:
α = 90.5m / (10m * 50°C)
α = 0.181 m/°C
Therefore, the linear expansivity of the brass is 0.181 m/°C.
Answered by
GPT 3.5
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