To find the efficiency of energy transfer between the harbor seal and the polar bear, we need to use the given formula:
(Energy level transferred to next level)
______________________________ X 100
(Total energy input)
The energy level transferred to the next level is 375 Kcal (from the harbor seal to the polar bear) and the total energy input is 2,500 Kcal (energy of the harbor seal).
Substituting these values into the formula:
(375 Kcal / 2,500 Kcal) X 100 = 0.15 X 100 = 15%
Therefore, the efficiency of energy transfer between the harbor seal and the polar bear is 15%, which is option D.
Use the following formula to find the efficiency of energy transfer between the harbor seal (2,500 Kcal) and a polar bear (375 Kcal).
(Energy level transferred to next level)
______________________________ X 100
(Total energy input)
A.) 20%
B.) 10%
C.) 12%
D.) 15%
1 answer