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Find the equation of the ellipse with vertices at (-1,3) and (5,3)and length of minor 4.
16 years ago

Answers

Reiny
first find the centre, which would be the midpoint of the vertices,
it would be (2,3)
the length of the minor axis is 4, so b = 2

sofar we would would have
(x-2)^2/a^2 + (y-3)^2/4 = 1
but (5,3) lies on it, so
(5-2)^2/a^2 + (3-3)^2/4 = 1
9/a^2 = 1
a^2 = 9

final equation
(x-2)^2/9 + (y-3)^2/4 = 1
16 years ago
confused
thanks!
16 years ago
vero
8(16)
16 years ago

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