Question

For each ordered pair, determine whether it is a solution to y=5x+6
2.16
-3.9
7,-52
-4,-14

Answer 1

To determine whether an ordered pair is a solution to an equation, we substitute the values into the equation and see if it holds true.

1) Let's substitute the first ordered pair, (2, 16), into the equation y=5x+6:
y = 5(2) + 6
y = 10 + 6
y = 16
The equation holds true when x = 2 and y = 16. Thus, (2, 16) is a solution to the equation y=5x+6.

2) Now let's substitute the second ordered pair, (-3, 9), into the equation y=5x+6:
y = 5(-3) + 6
y = -15 + 6
y = -9
The equation does not hold true when x = -3 and y = -9. Thus, (-3, 9) is not a solution to the equation y=5x+6.

3) For the third ordered pair, (7, -52), let's substitute it into the equation y=5x+6:
y = 5(7) + 6
y = 35 + 6
y = 41
The equation does not hold true when x = 7 and y = 41. Thus, (7, -52) is not a solution to the equation y=5x+6.

4) Lastly, let's substitute the last ordered pair, (-4, -14), into the equation y=5x+6:
y = 5(-4) + 6
y = -20 + 6
y = -14
The equation holds true when x = -4 and y = -14. Thus, (-4, -14) is a solution to the equation y=5x+6.